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Math Help
Topic Started: Jul 26 2010, 06:17 PM (299 Views)
Firestarter-
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Celeron 2
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A positive integer is more than twice a lesser positive integer by 5. adding the integer will result in a number close to 32. Give the equation.

hindi ko to alam -_-
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scisadmin
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parang mahirap ah.. kasi sabi nya, "close to 32" hmmm? how close?

pero try mo ung equation na to

a = 2(a) + 5
b = 2(a)
a + b = ("close to 32")

waaaaa?? tama ba? d ko kasi maxado magets ung prob.. :)
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Firestarter-
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Celeron 2
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onga eh.. hindi ko alam kung panu yung "CLOSE to 32". Ganun daw talaga yun eh
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MeanKitty
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Celeron 2
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Let a = larger integer and b = lesser integer.

a = 2b + 5 (Equation 1: "a" is more than twice "b" by 5)
a + b = 32
a = 32 - b (Equation 2)

a = a
2b + 5 = 32 - b
2b + b = 32 - 5
3b = 27
(3b) / 3 = 27 / 3
b = 9

a = 32 - b
a = 32 - 9
a = 23


Check:
a = 2b + 5
23 = 2(9) + 5
23 = 18 + 5
23 = 23 ;)
Simply put...
A positive integer is more than twice a lesser positive integer by 5.
"a" is more than twice "b" by 5
23 is more than twice 9 by 5
23 is more than 18 by 5
23 pesos is more than 18 pesos by 5 pesos
23 pesos > 18 by 5 pesos

Simple ain't it? B-)
Question: "23 pesos is greater than 18 pesos by how much?"
Answer: "5 pesos!"
Edited by MeanKitty, Jul 28 2010, 05:26 AM.
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insolence
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Dual Core
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a = 2b + 5 (Equation 1: "a" is more than twice "b" by 5)
a + b = 32
a = 32 - b (Equation 2)

diba po nakalagay sa question eh adding the integer will result in a number close to 32
di po ba a + b <> 32? or a + b != 32
I Played RF online and Became on of the TOP players
Then I got banned permanently cause of the DDM SK bug
I Played RF Olympic and Owned the Highlevels
Then I got banned for Camping Once
Yet the CW urge is still coming back to me
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MeanKitty
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Celeron 2
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Yeah, that part is kinda stupid. Haha! But what other number is closer to 32 than 32 itself, right?

If you don't like 32, then assume another integer that is close to 32 but divisible by 3. :)

35 for example...

a = 2b + 5 (Equation 1: "a" is more than twice "b" by 5)
a + b = 35 (assume a number close to 32)
a = 35 - b (Equation 2)

a = a
2b + 5 = 35 - b
2b + b = 35 - 5
3b = 30
(3b) / 3 = 30 / 3
b = 10

a = 35 - b
a = 35 - 10
a = 25

Check:
a = 2b + 5
25 = 2(10) + 5
25 = 20 + 5
25 = 25


Either way, you are still using the same equations. The instruction is to find the equation, not find the values of the integers.

So assuming it would be something like this...

a = 2b + 5 (Equation 1)
a + b = c (Equation 2)
c != 32 or c <> 32 (Equation 3)

Then that means...

2b + 5 = c - b
2b + b - c = 5
3b - c = 5 (Main Equation if searching for only 1 equation.)


The question itself is a little redundant since you can search for exact values given the first statement instead of values close something. Any number can be close to 32. Another answer would be leaving it as blank and say that the second statement is flawed. Because, if implied to a computer program, it would result to an infinite loop outputting numbers that are not equal to 32. LOL! ^_^
In other words, given the equations...
a = 2b + 5 (Equation 1)
a + b = c (Equation 2)
3b - c = 5 (Equation 3)

Substituting the value of c in Equation 2 from Equation 3...
3b - c = 5
3b - 5 = c

a + b = c
a + b = 3b - 5
a = 3b - b - 5
a = 2b - 5 (Equation 4)

Then using Equation 1...
a = 2b + b (Equation 1)
a = 2b - 5 (Equation 4)
2b + 5 = 2b - 5

2b - 2b = -5 - 5
0 = -10

OR

5 + 5 = 2b - 2b
10 = 0

Therefore, no answer. The second statement if flawed. XD
Edited by MeanKitty, Jul 28 2010, 02:04 PM.
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Firestarter-
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Celeron 2
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bigger number is 23, smaller number is 9. Here are the steps:

you have X and Y (x is bigger)

x=2y+5
x+y=32

substitute and you have
2y+5+y=32
simplify
3y+5=32
subtract 5 from both sides
3y=27
divide by 3
y=9

now plug 9 into the first formula
x=2(9)+5
x=23



same formula :) however.. shorter..

I really stupid at math!
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insolence
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MeanKitty
Jul 28 2010, 12:39 PM
Yeah, that part is kinda stupid. Haha! But what other number is closer to 32 than 32 itself, right?

If you don't like 32, then assume another integer that is close to 32 but divisible by 3. :)

35 for example...

a = 2b + 5 (Equation 1: "a" is more than twice "b" by 5)
a + b = 35 (assume a number close to 32)
a = 35 - b (Equation 2)

a = a
2b + 5 = 35 - b
2b + b = 35 - 5
3b = 30
(3b) / 3 = 30 / 3
b = 10

a = 35 - b
a = 35 - 10
a = 25

Check:
a = 2b + 5
25 = 2(10) + 5
25 = 20 + 5
25 = 25


Either way, you are still using the same equations. The instruction is to find the equation, not find the values of the integers.

So assuming it would be something like this...

a = 2b + 5 (Equation 1)
a + b = c (Equation 2)
c != 32 or c <> 32 (Equation 3)

Then that means...

2b + 5 = c - b
2b + b - c = 5
3b - c = 5 (Main Equation if searching for only 1 equation.)


The question itself is a little redundant since you can search for exact values given the first statement instead of values close something. Any number can be close to 32. Another answer would be leaving it as blank and say that the second statement is flawed. Because, if implied to a computer program, it would result to an infinite loop outputting numbers that are not equal to 32. LOL! ^_^
In other words, given the equations...
a = 2b + 5 (Equation 1)
a + b = c (Equation 2)
3b - c = 5 (Equation 3)

Substituting the value of c in Equation 2 from Equation 3...
3b - c = 5
3b - 5 = c

a + b = c
a + b = 3b - 5
a = 3b - b - 5
a = 2b - 5 (Equation 4)

Then using Equation 1...
a = 2b + b (Equation 1)
a = 2b - 5 (Equation 4)
2b + 5 = 2b - 5

2b - 2b = -5 - 5
0 = -10

OR

5 + 5 = 2b - 2b
10 = 0

Therefore, no answer. The second statement if flawed. XD
but i really admire the way you formulate your equations... pang mamaw na mathematician XD
baka naman ung next na number sa 32 using the same approach? its like in an array of answers
...[q][r][32][t]... you can derive your answer by using r and s? 0_ohehe demn ang galing mo sa pagformulate ng equations... idol!
Edited by insolence, Jul 28 2010, 10:52 PM.
I Played RF online and Became on of the TOP players
Then I got banned permanently cause of the DDM SK bug
I Played RF Olympic and Owned the Highlevels
Then I got banned for Camping Once
Yet the CW urge is still coming back to me
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MeanKitty
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Celeron 2
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Firestarter-
Jul 28 2010, 07:46 PM
bigger number is 23, smaller number is 9. Here are the steps:

you have X and Y (x is bigger)

x=2y+5
x+y=32

substitute and you have
2y+5+y=32
simplify
3y+5=32
subtract 5 from both sides
3y=27
divide by 3
y=9

now plug 9 into the first formula
x=2(9)+5
x=23



same formula :) however.. shorter..

I really stupid at math!
Uhm??? You just repeated my first post only with "x" and "y" instead of "a" and "b". You just didn't include a detailed explanation for others to understand. :blink:
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Firestarter-
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Celeron 2
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MeanKitty
Jul 29 2010, 05:53 AM
Firestarter-
Jul 28 2010, 07:46 PM
bigger number is 23, smaller number is 9. Here are the steps:

you have X and Y (x is bigger)

x=2y+5
x+y=32

substitute and you have
2y+5+y=32
simplify
3y+5=32
subtract 5 from both sides
3y=27
divide by 3
y=9

now plug 9 into the first formula
x=2(9)+5
x=23



same formula :) however.. shorter..

I really stupid at math!
Uhm??? You just repeated my first post only with "x" and "y" instead of "a" and "b". You just didn't include a detailed explanation for others to understand. :blink:
hindi ko ni repeat yan. mas naunang sagot yan :) sa facebook
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MeanKitty
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@insolence
Like I said, there are multiple answers depending on the person who gave the statements in the first place. Might as well give all of them.

The following are possible answers to the problem:
1. Assuming the statement "close to 32" was just meant to confuse you. The answer would be using the value 32 as a reference to the equations. This would then result to exact and constant values for the larger and lesser integers.
2. Assuming the statement "close to 32" was meant as a value not equal to 32. This would make you use values literally "close to 32". This would still result to exact values for the larger and lesser integers.
3. Assuming one of the statements is flawed, resulting to the answer being blank. The problem was not made to be solved in the first place.
4. Assuming the problem itself is flawed, and the answer being all of the above.
5. Just follow the instructions and give only the equations without any specific values. :P

Whatever the answer, I still stand by me opinion that the second statement is redundant or flawed. It is just like asking your friend to give a name of a person close to Harry. There would be numerous answers that your friend can give you. Examples would be: Mary, Cherry, Barry, Larry, etc.
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